In the initial echo command, the apostrophes prevent interpretation of the variable, instead yielding a verbatim copy of the quoted text, the four-letter string$ var. 在第一个echo命令中,单引号禁止解释此变量,因此会按原样显示引号中的文本,即四字母的字符串$var。
You will define a string to be a QUOTED_STRING if it begins with a quote, ends with a quote and has any other character in between. 如果您定义一个以引号开头,以引号结尾并在其中包含任何其他字符的字符串,那么该字符串就是一个QUOTEDSTRING。
Hint: A leading# character indicates the start of a comment, unless it is within a quoted string. 提示:除非是在引用的字符串以内,否则开头的字符就表示注释开始。
For one thing, the code is in one big quoted string. 一方面,该代码是在一个大引证字符串中。
The path must be a quoted string. 路径必须是带引号的字符串。
Need to extract a zip code, phone number, or quoted string? Try Nathan's solutions. 如果需要提取邮政编码、电话号码或引用的字符串,请尝试Nathan的解决方案。
Wisely, it doesn't replace a comma found within a quoted string. 它很聪明,不会替换在引号括起的字符串中找到的逗号。
Put the comparands into a form that DB2 can understand, for example remove the double quotes from QUOTED_STRING tokens 将比较字(comparand)转换为DB2可以理解的形式,例如,除去QUOTEDSTRING标记的双引号
You can't just take a quoted string back to back with another quoted string so you'd get some kind of compiler error. 你不能让一个引起来的字符串跟另一个引起来的字符串,背靠背,这样编译就会出错。
A quoted string was expected near line% 1. 带引号的字符串应该出现在第%1行附近。